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6x^2+3x=630
We move all terms to the left:
6x^2+3x-(630)=0
a = 6; b = 3; c = -630;
Δ = b2-4ac
Δ = 32-4·6·(-630)
Δ = 15129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15129}=123$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-123}{2*6}=\frac{-126}{12} =-10+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+123}{2*6}=\frac{120}{12} =10 $
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